Expanding the Quadratic Expressions

Oct 13, 2025 by talynt.org 7 views

=====================================================

Introduction

In this article, we will delve into the world of algebra and explore a complex equation that requires a combination of mathematical techniques to solve. The equation in question is:

(2x + 1)^2 - 4(x - 3)^2 = 5x + 10

This equation involves quadratic expressions, which can be challenging to work with. However, with a systematic approach and a solid understanding of algebraic manipulations, we can break down the equation and find its solution.

Expanding the Quadratic Expressions

The first step in solving this equation is to expand the quadratic expressions on both sides. We will start with the left-hand side:

(2x + 1)^2 - 4(x - 3)^2

Using the formula $(a + b)^2 = a^2 + 2ab + b^2$ , we can expand the first term:

(2x + 1)^2 = (2x)^2 + 2(2x)(1) + 1^2

Simplifying the expression, we get:

(2x + 1)^2 = 4x^2 + 4x + 1

Now, let's expand the second term:

-4(x - 3)^2 = -4(x^2 - 6x + 9)

Using the distributive property, we can expand the expression:

-4(x^2 - 6x + 9) = -4x^2 + 24x - 36

Now, we can combine the two expanded expressions:

(2x + 1)^2 - 4(x - 3)^2 = 4x^2 + 4x + 1 - 4x^2 + 24x - 36

Simplifying the expression, we get:

(2x + 1)^2 - 4(x - 3)^2 = 28x - 35

Simplifying the Right-Hand Side

The right-hand side of the equation is a linear expression:

5x + 10

Equating the Two Sides

Now that we have simplified both sides of the equation, we can equate them:

28x - 35 = 5x + 10

Solving for x

To solve for x, we can use the following steps:

Add 35 to both sides of the equation:

28x = 5x + 45

Subtract 5x from both sides of the equation:

23x = 45

Divide both sides of the equation by 23:

x = \frac{45}{23}

Conclusion

In this article, we have solved a complex equation involving quadratic expressions. By expanding the quadratic expressions, simplifying the right-hand side, and equating the two sides, we were able to find the solution to the equation. The final answer is:

x = \frac{45}{23}

This solution can be verified by plugging it back into the original equation.

Final Thoughts

Solving equations like this one requires a combination of mathematical techniques, including expanding quadratic expressions, simplifying linear expressions, and equating the two sides. By following a systematic approach and using algebraic manipulations, we can break down complex equations and find their solutions. Whether you're a student or a professional, mastering these techniques will help you tackle even the most challenging mathematical problems.

Additional Resources

If you're interested in learning more about algebra and solving equations, here are some additional resources:

Khan Academy: Algebra
MIT OpenCourseWare: Algebra
Wolfram Alpha: Algebra Solver

These resources provide a wealth of information and practice problems to help you improve your skills in algebra and solving equations.

FAQs

Here are some frequently asked questions about solving equations like this one:

Q: What is the first step in solving an equation like this one? A: The first step is to expand the quadratic expressions on both sides of the equation.
Q: How do I simplify a linear expression like 5x + 10? A: To simplify a linear expression, you can combine like terms and perform any necessary arithmetic operations.
Q: What is the final answer to the equation? A: The final answer is x = 45/23.

I hope this article has been helpful in providing a step-by-step guide to solving the equation. If you have any questions or need further clarification, please don't hesitate to ask.

=====================================

Introduction

In our previous article, we explored a complex equation involving quadratic expressions and provided a step-by-step guide to solving it. However, we know that sometimes, the best way to learn is through questions and answers. In this article, we will address some of the most frequently asked questions about solving equations like this one.

Q&A

Q: What is the first step in solving an equation like this one?

A: The first step in solving an equation like this one is to expand the quadratic expressions on both sides of the equation. This involves using the formula (a + b)^2 = a^2 + 2ab + b^2 to expand the expressions.

Q: How do I simplify a linear expression like 5x + 10?

A: To simplify a linear expression like 5x + 10, you can combine like terms and perform any necessary arithmetic operations. In this case, the expression is already simplified, but if you had an expression like 3x + 5 + 2x, you would combine the like terms to get 5x + 5.

Q: What is the difference between a quadratic expression and a linear expression?

A: A quadratic expression is an expression that involves a squared variable, such as x^2 or (x + 1)^2. A linear expression, on the other hand, is an expression that involves only a single variable, such as x or 2x + 3.

Q: How do I know when to use the distributive property?

A: The distributive property is a mathematical property that states that a(b + c) = ab + ac. You can use the distributive property when you have an expression like a(b + c) and you want to expand it.

Q: What is the final answer to the equation?

A: The final answer to the equation is x = 45/23.

Q: Can I use a calculator to solve equations like this one?

A: Yes, you can use a calculator to solve equations like this one. However, it's always a good idea to check your work by plugging the solution back into the original equation.

Q: What if I get stuck on a problem like this one?

A: If you get stuck on a problem like this one, don't be afraid to ask for help. You can ask a teacher, a tutor, or a classmate for assistance. You can also try breaking the problem down into smaller steps or looking for online resources to help you understand the concept.

Conclusion

Solving equations like this one requires a combination of mathematical techniques, including expanding quadratic expressions, simplifying linear expressions, and equating the two sides. By following a systematic approach and using algebraic manipulations, we can break down complex equations and find their solutions. We hope this Q&A guide has been helpful in providing additional support and clarification on solving equations like this one.

Additional Resources

If you're interested in learning more about algebra and solving equations, here are some additional resources:

Khan Academy: Algebra
MIT OpenCourseWare: Algebra
Wolfram Alpha: Algebra Solver

These resources provide a wealth of information and practice problems to help you improve your skills in algebra and solving equations.

Final Thoughts

Solving equations like this one requires patience, persistence, and practice. Don't be discouraged if you struggle at first – with time and effort, you'll become more confident and proficient in solving equations like this one. Remember to always check your work and ask for help when you need it. Good luck!