Science 9 PO YAN 4th Discussion

Oct 13, 2025 by talynt.org 133 views

Understanding the Problem

In this problem, we are given the initial velocity of an object, the time it takes to reach a certain height, and the distance it travels horizontally. We need to determine the height of the table. This problem involves the application of kinematic equations in physics, specifically the equations of motion under constant acceleration.

Given Values

Initial time (t) = 0.70 m
Initial velocity (vi) = 1.50 m/s
Time (t) = 0.47 s
Horizontal distance (dx) = 0.20 m
Acceleration due to gravity (ag) = 9.8 m/s²

Calculating the Height

To calculate the height of the table, we need to use the equation of motion under constant acceleration:

dy = vi × t + (1/2) × ag × t²

where dy is the height of the table, vi is the initial velocity, t is the time, and ag is the acceleration due to gravity.

Step 1: Calculate the Height

First, we need to calculate the height of the table using the given values:

dy = vi × t + (1/2) × ag × t² = 1.50 m/s × 0.47 s + (1/2) × 9.8 m/s² × (0.47 s)² = 0.705 m + 1.065 m = 1.77 m

Step 2: Calculate the Horizontal Distance

Next, we need to calculate the horizontal distance traveled by the object:

dx = vi × t = 1.50 m/s × 0.47 s = 0.705 m

Step 3: Calculate the Vertical Distance

Now, we need to calculate the vertical distance traveled by the object:

dy = (1/2) × ag × t² = (1/2) × 9.8 m/s² × (0.47 s)² = 1.065 m

Conclusion

In this problem, we used the kinematic equations to calculate the height of the table. We first calculated the height using the equation of motion under constant acceleration, and then calculated the horizontal distance and vertical distance traveled by the object. The final answer is:

The height of the table is 1.77 m.

Science 9 PO YAN 4th Discussion

Understanding the Problem

Given Values

Initial time (t) = 0.70 m
Initial velocity (vi) = 1.50 m/s
Time (t) = 0.47 s
Horizontal distance (dx) = 0.20 m
Acceleration due to gravity (ag) = 9.8 m/s²

Calculating the Height

To calculate the height of the table, we need to use the equation of motion under constant acceleration:

dy = vi × t + (1/2) × ag × t²

where dy is the height of the table, vi is the initial velocity, t is the time, and ag is the acceleration due to gravity.

Step 1: Calculate the Height

First, we need to calculate the height of the table using the given values:

dy = vi × t + (1/2) × ag × t² = 1.50 m/s × 0.47 s + (1/2) × 9.8 m/s² × (0.47 s)² = 0.705 m + 1.065 m = 1.77 m

Step 2: Calculate the Horizontal Distance

Next, we need to calculate the horizontal distance traveled by the object:

dx = vi × t = 1.50 m/s × 0.47 s = 0.705 m

Step 3: Calculate the Vertical Distance

Now, we need to calculate the vertical distance traveled by the object:

dy = (1/2) × ag × t² = (1/2) × 9.8 m/s² × (0.47 s)² = 1.065 m

Conclusion

The height of the table is 1.77 m.

Science 9 PO YAN 4th Discussion

Understanding the Problem: In this problem, we are given the initial velocity of an object, the time it takes to reach a certain height, and the distance it travels horizontally. We need to determine the height of the table. This problem involves the application of kinematic equations in physics, specifically the equations of motion under constant acceleration.
Given Values: The given values are:
- Initial time (t) = 0.70 m
- Initial velocity (vi) = 1.50 m/s
- Time (t) = 0.47 s
- Horizontal distance (dx) = 0.20 m
- Acceleration due to gravity (ag) = 9.8 m/s²
Calculating the Height: To calculate the height of the table, we need to use the equation of motion under constant acceleration:
- dy = vi × t + (1/2) × ag × t²
- where dy is the height of the table, vi is the initial velocity, t is the time, and ag is the acceleration due to gravity.
Step 1: Calculate the Height: First, we need to calculate the height of the table using the given values:
- dy = vi × t + (1/2) × ag × t²
- = 1.50 m/s × 0.47 s + (1/2) × 9.8 m/s² × (0.47 s)²
- = 0.705 m + 1.065 m
- = 1.77 m
Step 2: Calculate the Horizontal Distance: Next, we need to calculate the horizontal distance traveled by the object:
- dx = vi × t
- = 1.50 m/s × 0.47 s
- = 0.705 m
Step 3: Calculate the Vertical Distance: Now, we need to calculate the vertical distance traveled by the object:
- dy = (1/2) × ag × t²
- = (1/2) × 9.8 m/s² × (0.47 s)²
- = 1.065 m
Conclusion: In this problem, we used the kinematic equations to calculate the height of the table. We first calculated the height using the equation of motion under constant acceleration, and then calculated the horizontal distance and vertical distance traveled by the object. The final answer is:
- The height of the table is 1.77 m.
  Q&A: How High is the Table? =============================

Frequently Asked Questions

In this article, we will answer some of the most frequently asked questions related to the problem of determining the height of a table.

Q: What is the initial velocity of the object?

A: The initial velocity of the object is 1.50 m/s.

Q: What is the time it takes for the object to reach a certain height?

A: The time it takes for the object to reach a certain height is 0.47 s.

Q: What is the horizontal distance traveled by the object?

A: The horizontal distance traveled by the object is 0.20 m.

Q: What is the acceleration due to gravity?

A: The acceleration due to gravity is 9.8 m/s².

Q: How do I calculate the height of the table?

A: To calculate the height of the table, you need to use the equation of motion under constant acceleration:

dy = vi × t + (1/2) × ag × t²

where dy is the height of the table, vi is the initial velocity, t is the time, and ag is the acceleration due to gravity.

Q: What is the formula for calculating the height of the table?

A: The formula for calculating the height of the table is:

dy = vi × t + (1/2) × ag × t²

Q: How do I calculate the horizontal distance traveled by the object?

A: To calculate the horizontal distance traveled by the object, you need to use the equation:

dx = vi × t

where dx is the horizontal distance, vi is the initial velocity, and t is the time.

Q: What is the formula for calculating the horizontal distance traveled by the object?

A: The formula for calculating the horizontal distance traveled by the object is:

dx = vi × t

Q: How do I calculate the vertical distance traveled by the object?

A: To calculate the vertical distance traveled by the object, you need to use the equation:

dy = (1/2) × ag × t²

where dy is the vertical distance, ag is the acceleration due to gravity, and t is the time.

Q: What is the formula for calculating the vertical distance traveled by the object?

A: The formula for calculating the vertical distance traveled by the object is:

dy = (1/2) × ag × t²

Q: What is the final answer to the problem?

A: The final answer to the problem is:

The height of the table is 1.77 m.

Common Mistakes to Avoid

When solving the problem of determining the height of a table, there are several common mistakes to avoid. These include:

Incorrectly calculating the height of the table: Make sure to use the correct formula and values when calculating the height of the table.
Incorrectly calculating the horizontal distance traveled by the object: Make sure to use the correct formula and values when calculating the horizontal distance traveled by the object.
Incorrectly calculating the vertical distance traveled by the object: Make sure to use the correct formula and values when calculating the vertical distance traveled by the object.
Not using the correct values for the initial velocity, time, and acceleration due to gravity: Make sure to use the correct values for the initial velocity, time, and acceleration due to gravity when solving the problem.

Conclusion

In this article, we have answered some of the most frequently asked questions related to the problem of determining the height of a table. We have also discussed common mistakes to avoid when solving the problem. By following the correct formulas and using the correct values, you can accurately determine the height of a table.