Solving System 4 using Substitution

Oct 13, 2025 by talynt.org 107 views

Introduction

In mathematics, a system of linear equations is a set of two or more equations that involve two or more variables. Solving a system of linear equations means finding the values of the variables that satisfy all the equations in the system. There are several methods to solve a system of linear equations, including substitution, elimination, and graphing. In this article, we will focus on solving systems of linear equations using the substitution method.

What is the Substitution Method?

The substitution method is a technique used to solve a system of linear equations by substituting the expression for one variable from one equation into the other equation. This method is useful when one of the equations is already solved for one of the variables. The substitution method involves the following steps:

Solve one of the equations for one of the variables.
Substitute the expression for the variable into the other equation.
Solve the resulting equation for the other variable.
Back-substitute the value of the variable into one of the original equations to find the value of the other variable.

Solving System 4 using Substitution

System 4

{ \begin{align*} y &= \frac{1}{2}x + 4 \\ x - y &= 8 \end{align*} \}

To solve this system using substitution, we can start by solving the first equation for y.

{ y = \frac{1}{2}x + 4 }

Now, substitute this expression for y into the second equation.

{ x - \left(\frac{1}{2}x + 4\right) = 8 }

Simplify the equation.

{ x - \frac{1}{2}x - 4 = 8 }

Combine like terms.

{ \frac{1}{2}x - 4 = 8 }

Add 4 to both sides of the equation.

{ \frac{1}{2}x = 12 }

Multiply both sides of the equation by 2.

{ x = 24 }

Now, substitute the value of x into one of the original equations to find the value of y.

{ y = \frac{1}{2}(24) + 4 }

Simplify the equation.

{ y = 12 + 4 }

{ y = 16 }

Therefore, the solution to System 4 is x = 24 and y = 16.

Solving System 5 using Substitution

System 5

{ \begin{align*} 3.25x - 1.5y &= 1.25 \\ 13x - 6y &= 10 \end{align*} \}

To solve this system using substitution, we can start by solving the first equation for y.

{ -1.5y = -3.25x + 1.25 }

Divide both sides of the equation by -1.5.

{ y = \frac{3.25}{1.5}x - \frac{1.25}{1.5} }

Simplify the equation.

{ y = 2.1667x - 0.8333 }

Now, substitute this expression for y into the second equation.

{ 13x - 6\left(2.1667x - 0.8333\right) = 10 }

Simplify the equation.

{ 13x - 12.9996x + 5 = 10 }

Combine like terms.

{ 0.0004x + 5 = 10 }

Subtract 5 from both sides of the equation.

{ 0.0004x = 5 }

Divide both sides of the equation by 0.0004.

{ x = \frac{5}{0.0004} }

Simplify the equation.

{ x = 12500 }

Now, substitute the value of x into one of the original equations to find the value of y.

{ y = 2.1667(12500) - 0.8333 }

Simplify the equation.

{ y = 27166.75 - 0.8333 }

{ y = 27166 }

Therefore, the solution to System 5 is x = 12500 and y = 27166.

Solving System 6 using Substitution

System 6

{ \begin{align*} y - 0.8x &= 0.5 \\ 13x - 6y &= 10 \end{align*} \}

To solve this system using substitution, we can start by solving the first equation for y.

{ y = 0.8x + 0.5 }

Now, substitute this expression for y into the second equation.

{ 13x - 6\left(0.8x + 0.5\right) = 10 }

Simplify the equation.

{ 13x - 4.8x - 3 = 10 }

Combine like terms.

{ 8.2x - 3 = 10 }

Add 3 to both sides of the equation.

{ 8.2x = 13 }

Divide both sides of the equation by 8.2.

{ x = \frac{13}{8.2} }

Simplify the equation.

{ x = 1.585 }

Now, substitute the value of x into one of the original equations to find the value of y.

{ y = 0.8(1.585) + 0.5 }

Simplify the equation.

{ y = 1.268 + 0.5 }

{ y = 1.768 }

Therefore, the solution to System 6 is x = 1.585 and y = 1.768.

Conclusion

Q: What is the substitution method?

A: The substitution method is a technique used to solve a system of linear equations by substituting the expression for one variable from one equation into the other equation.

Q: When should I use the substitution method?

A: You should use the substitution method when one of the equations is already solved for one of the variables. This method is useful when you can easily substitute the expression for the variable into the other equation.

Q: How do I solve a system of linear equations using substitution?

A: To solve a system of linear equations using substitution, follow these steps:

Solve one of the equations for one of the variables.
Substitute the expression for the variable into the other equation.
Solve the resulting equation for the other variable.
Back-substitute the value of the variable into one of the original equations to find the value of the other variable.

Q: What if I have two equations with two variables, but neither equation is solved for one of the variables?

A: In this case, you can use the elimination method to solve the system of linear equations. The elimination method involves adding or subtracting the equations to eliminate one of the variables.

Q: Can I use the substitution method to solve a system of linear equations with more than two variables?

A: Yes, you can use the substitution method to solve a system of linear equations with more than two variables. However, the process may be more complicated and may require more steps.

Q: What if I have a system of linear equations with fractions or decimals?

A: You can still use the substitution method to solve a system of linear equations with fractions or decimals. Simply follow the same steps as before, and be sure to simplify the equations as you go.

Q: How do I know if the solution to a system of linear equations is unique?

A: To determine if the solution to a system of linear equations is unique, you can check if the equations are consistent and if the solution satisfies both equations. If the solution satisfies both equations, then it is a unique solution.

Q: What if I have a system of linear equations with no solution?

A: If you have a system of linear equations with no solution, it means that the equations are inconsistent. This can happen if the equations are contradictory, such as 2x + 3y = 5 and 2x + 3y = 7.

Q: Can I use the substitution method to solve a system of linear equations with dependent variables?

A: Yes, you can use the substitution method to solve a system of linear equations with dependent variables. However, the solution will be an infinite number of solutions, and you will need to express the solution in terms of a parameter.

Conclusion

In this article, we have answered some frequently asked questions about solving systems of linear equations using the substitution method. The substitution method is a powerful tool for solving systems of linear equations, and it can be used to solve systems with two or more variables. By following the steps outlined in this article, you can use the substitution method to solve a wide range of systems of linear equations.