The Divisibility Condition

Oct 13, 2025 by talynt.org 82 views

Introduction

When a polynomial is divisible by (x-1), it means that the polynomial has a root at x=1. In other words, if we substitute x=1 into the polynomial, the result should be zero. In this article, we will explore the value of k such that the polynomial k^2 x^3 - 6kx + 9 is divisible by (x-1).

The Divisibility Condition

For a polynomial to be divisible by (x-1), it must have a root at x=1. This means that when we substitute x=1 into the polynomial, the result should be zero. Mathematically, this can be expressed as:

k^2 (1)^3 - 6k(1) + 9 = 0

Simplifying the equation, we get:

k^2 - 6k + 9 = 0

Solving the Quadratic Equation

The equation k^2 - 6k + 9 = 0 is a quadratic equation in the form ax^2 + bx + c = 0. To solve for k, we can use the quadratic formula:

k = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 1, b = -6, and c = 9. Plugging these values into the quadratic formula, we get:

k = (6 ± √((-6)^2 - 4(1)(9))) / 2(1) k = (6 ± √(36 - 36)) / 2 k = (6 ± √0) / 2 k = 6 / 2 k = 3

Conclusion

Therefore, the value of k such that the polynomial k^2 x^3 - 6kx + 9 is divisible by (x-1) is k = 3.

The Significance of the Result

The result k = 3 has significant implications for the polynomial k^2 x^3 - 6kx + 9. When k = 3, the polynomial becomes:

(3)^2 x^3 - 6(3)x + 9 9x^3 - 18x + 9

This polynomial is divisible by (x-1), which means that it has a root at x=1. This is a fundamental property of polynomials and has important applications in mathematics and science.

The Generalization of the Result

The result k = 3 can be generalized to any polynomial of the form k^2 x^3 - 6kx + 9. When k = 3, the polynomial is divisible by (x-1), regardless of the value of x. This means that the polynomial has a root at x=1, which is a fundamental property of polynomials.

The Implications of the Result

The result k = 3 has significant implications for the study of polynomials and their properties. It highlights the importance of the value of k in determining the divisibility of a polynomial by (x-1). This result has important applications in mathematics and science, particularly in the study of polynomial equations and their roots.

The Future of Polynomial Research

The result k = 3 is a significant contribution to the field of polynomial research. It highlights the importance of the value of k in determining the divisibility of a polynomial by (x-1). This result has important implications for the study of polynomial equations and their roots, and it will likely have a significant impact on the future of polynomial research.

Conclusion

In conclusion, the value of k such that the polynomial k^2 x^3 - 6kx + 9 is divisible by (x-1) is k = 3. This result has significant implications for the study of polynomials and their properties, and it will likely have a significant impact on the future of polynomial research.

Introduction

In our previous article, we explored the value of k such that the polynomial k^2 x^3 - 6kx + 9 is divisible by (x-1). In this article, we will answer some frequently asked questions (FAQs) about the divisibility of a polynomial by (x-1).

Q: What is the significance of the value of k in determining the divisibility of a polynomial by (x-1)?

A: The value of k determines whether the polynomial is divisible by (x-1). When k = 3, the polynomial is divisible by (x-1), which means that it has a root at x=1.

Q: How do I determine if a polynomial is divisible by (x-1)?

A: To determine if a polynomial is divisible by (x-1), you need to substitute x=1 into the polynomial and check if the result is zero. If the result is zero, then the polynomial is divisible by (x-1).

Q: What is the relationship between the value of k and the roots of the polynomial?

A: The value of k determines the roots of the polynomial. When k = 3, the polynomial has a root at x=1. This means that when x=1, the polynomial is equal to zero.

Q: Can a polynomial be divisible by (x-1) if it has no real roots?

A: Yes, a polynomial can be divisible by (x-1) even if it has no real roots. This is because the polynomial may have complex roots that are not real.

Q: How do I find the value of k such that a polynomial is divisible by (x-1)?

A: To find the value of k such that a polynomial is divisible by (x-1), you need to substitute x=1 into the polynomial and solve for k. This will give you the value of k that makes the polynomial divisible by (x-1).

Q: Can a polynomial be divisible by (x-1) if it has a degree greater than 3?

A: Yes, a polynomial can be divisible by (x-1) even if it has a degree greater than 3. This is because the polynomial may have a root at x=1, even if it has a higher degree.

Q: What is the relationship between the value of k and the coefficients of the polynomial?

A: The value of k determines the coefficients of the polynomial. When k = 3, the coefficients of the polynomial are 9, -18, and 9.

Q: Can a polynomial be divisible by (x-1) if it has a constant term?

A: Yes, a polynomial can be divisible by (x-1) even if it has a constant term. This is because the constant term does not affect the divisibility of the polynomial by (x-1).

Conclusion

In conclusion, the value of k determines whether a polynomial is divisible by (x-1). When k = 3, the polynomial is divisible by (x-1), which means that it has a root at x=1. We hope that this article has answered some of the frequently asked questions about the divisibility of a polynomial by (x-1).

Additional Resources

For more information about the divisibility of a polynomial by (x-1), please refer to the following resources:

[1] "Polynomial Division" by Math Open Reference
[2] "Divisibility of Polynomials" by Wolfram MathWorld
[3] "Polynomial Roots" by Khan Academy

We hope that this article has been helpful in understanding the divisibility of a polynomial by (x-1. If you have any further questions, please do not hesitate to contact us.